(1)/(216)=36^(3x+6)

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Solution for (1)/(216)=36^(3x+6) equation: 



(1)/(216)=36^(3x+6)

We move all terms to the left:

(1)/(216)-(36^(3x+6))=0

We multiply all the terms by the denominator


-((36^(3x+6)))*216+1=0

We move all terms containing x to the left, all other terms to the right

-((36^(3x+6)))*216=-1

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